With the solution of this question another possibility of the way A is
to be used ( see step 120):
The compound contains a phenyl group of C6H5.
Thus C4H5O must be looked
up for univalent remainder, fitting the spectrum. The small number of
H-atoms suggests that multiple bonds and thus possibly "long range"
- Predicates from the chemical shifts of the signals:
- Analysis of intensities and couplings:
- The multiplicity of the signals with d = 2.3 ppm and d = 4.1 ppm shows that CH2-
group with a CH-group couples: HC- · · · ·
The intensities acknowledge this findings.
From the structures possible for the first signal is applicable thus
only CºC-. Altogether we
- The singlet signal with d
= 4.6 ppm with same intensity as the Dublett can come then only from
not coupling CH 2 - group.
- Check on the basis the sum formula:
Since the univalent remainder contains only four C-atoms, the following
structure corresponding with the spectrum comes into consideration: HCºC-CH2-O-CH2-
Solve the next question now.