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You wouldn't have picked this solution if you would have tried to draw the structure of this cyclopropane derivative E. Because then it would have been obvious to you that this isomer would have to give rise to four proton signals. Raumformel Isomeres E
Besides, is there a proton in this molecule that might give rise to a signal with a chemical shift d = 9.9 ppm ?

Go back to page 48 and give it another try!