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Great! Your answer is right.

The signal of the proton HA in
ClCH = CH - CH2Cl
M   A   X
is split into
six individual lines, since HM and HX are not equivalent. Therefore their spin-spin couplings to HA are independent from each other. HA gives rise to a multiplet with

MA = (nM + 1) (nX + 1).

Did you arrive at a different answer? Check on page 91 for additional explanations.

Continuing from here, what would be the ratio of the intensities of the individual lines in the HA signal be?

Compare your answer to the solution on page 101!