Great! Your answer is right.
six individual lines, since HM
are not equivalent. Therefore their spin-spin couplings to HA are
independent from each other. HA
gives rise to a multiplet with
|The signal of the proton HA in
|| is split into
+ 1) · (nX
||Did you arrive at a different answer? Check on page 91 for additional explanations.
| Continuing from here, what would be the ratio of
the intensities of the individual lines in the HA
Compare your answer to the solution on page