92

Great! Your answer is right.
The signal of the proton H^{A} in 
ClCH 
= 
CH 
 
CH_{2}Cl 
M 

A 

X 

is split into 
six individual lines, since H^{M}
and H^{X}
are not equivalent. Therefore their spinspin couplings to H^{A} are
independent from each other. H^{A}
gives rise to a multiplet with
M_{A}
= (n_{M}
+ 1) · (n_{X}
+ 1). 

Did you arrive at a different answer? Check on page 91 for additional explanations. 
Continuing from here, what would be the ratio of
the intensities of the individual lines in the H^{A}
signal be?
Compare your answer to the solution on page
101! 
