relative intensities of the multiplet lines for the signal of HA can be
derived based on the coupling constants, as shown in this example:
|For the molecule
||the number as well as the
The given values for HA
The coupling between HA
gives rise to a doublet (nM =
1; relative intensities 1 : 1). Due to the second,
independent coupling with HX,
the two doublet lines are additionally split into triplets (nX
= 2; relative intensities
1 : 2 : 1). In total there are
therefore six lines (MA = 6).
= 4,86 ppm; JAM = 13,1 Hz; JAX
= 7,3 Hz.
| Now, what are the relative intensities of the
six lines of the HA-signal?
Check for the right answer here!