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For the molecule

ClCH	=	CH	-	CH₂Cl
M		A		X

the number as well as the

relative intensities of the multiplet lines for the signal of H^A can be derived based on the coupling constants, as shown in this example:
The given values for H^A are:

d_A = 4,86 ppm; J_AM = 13,1 Hz; J_AX = 7,3 Hz.

The coupling between H^A and H^M gives rise to a doublet (n_M = 1; relative intensities 1 : 1). Due to the second, independent coupling with H^X, the two doublet lines are additionally split into triplets (n_X = 2; relative intensities 1 : 2 : 1). In total there are therefore six lines (M_A = 6).

Now, what are the relative intensities of the six lines of the H^A-signal?

Check for the right answer here!